'''
Created on 2011-8-8

@author: songxk
'''


#str = '12345678'
#for item in ['0x%s' % (str[i:i+2]) for i in range(len(str) / 2)]:
#    print item
    

#import re
#str = '12345ABCD'
#result = ['0x' + m for m in re.findall('\\w{2}',str) ]
#for item in result:
#    print item

str1 = '111'
str2 = '222'
#str2 += '/%s' % str1
str2 = str2 + str1
print str2